def dec(bytestr):
positions = {
0: 7,
1: 5,
2: 4,
3: 3,
4: 6,
5: 2,
6: 1,
7: 0,
}
res = []
for c in bytestr:
outc = 0x2800
for i in range(0, 8):
if c & (1 << i):
outc |= (1 << positions[i])
res.append(outc)
return ''.join([chr(b) for b in res])
Replies to Untitled 
| Title |
Name |
Language |
UNIX |
When |
| Re: Untitled |
anonymous |
python |
1666618309 |
7 Months ago. |
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